304Bobcat
New Member
I purchased a 1999 Bobcat 331 serial 512918539 few months back and I am in the process of getting everything back to working order. I installed two new final drives, new 2speed solenoid, and new foot switch. After installation nothing happens when foot switch is pushed while track is traveling in either direction.
So I did a little testing and I have 12v power (hot and ground) coming into the foot switch. I have 12v power coming into the solenoid if I push and hold the foot switch. So the foot switch doesnt switch power on and off but only connects power to the solenoid while pushed in only, once released power is cut to the solenoid.
My question then is..... is the solenoid a pulse style solenoid which just takes a brief pulse of energy to move and hold the valve open or closed in the Accumulator? Im trying to understand how the solenoid and valve work. Obviously the solenoid doesnt get constant 12v power like I would have thought in order to energize the magnet and pull up the valve stem. So does anyone how this solenoid valve works? It seems to me nothing is happening with the valve in the accumulator when power is sent to the solenoid.
So I did a little testing and I have 12v power (hot and ground) coming into the foot switch. I have 12v power coming into the solenoid if I push and hold the foot switch. So the foot switch doesnt switch power on and off but only connects power to the solenoid while pushed in only, once released power is cut to the solenoid.
My question then is..... is the solenoid a pulse style solenoid which just takes a brief pulse of energy to move and hold the valve open or closed in the Accumulator? Im trying to understand how the solenoid and valve work. Obviously the solenoid doesnt get constant 12v power like I would have thought in order to energize the magnet and pull up the valve stem. So does anyone how this solenoid valve works? It seems to me nothing is happening with the valve in the accumulator when power is sent to the solenoid.